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(F)=10.000-250F^2
We move all terms to the left:
(F)-(10.000-250F^2)=0
We get rid of parentheses
250F^2+F-10.000=0
We add all the numbers together, and all the variables
250F^2+F-10=0
a = 250; b = 1; c = -10;
Δ = b2-4ac
Δ = 12-4·250·(-10)
Δ = 10001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{10001}}{2*250}=\frac{-1-\sqrt{10001}}{500} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{10001}}{2*250}=\frac{-1+\sqrt{10001}}{500} $
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